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Home > AC > Chapter 8 > Lesson 8.1.3 > Problem 8-30

8-30.

One strategy is to set the equations equal to each other to solve for x.

4x − 3 = 9x − 13
10 = 5x
2 = x

Now substitute x back into one of the original equations to solve for y.

y = 4(2) − 3
y = 8 − 3
y = 5

The two lines intersect at (2, 5).