### Home > CAAC > Chapter 10 > Lesson 10.1.2 > Problem10-18

10-18.

Now David wants to solve the equation $4000x-8000=16{,}000$.

1. What easier equation could he solve instead that would give him the same solution? (In other words, what equivalent equation has easier numbers to work with?)

Divide both sides of the equation by the greatest common factor.

$x−2=4$

2. Justify that your equation in part (a) is equivalent to $4000x-8000=16,000$ by showing that they have the same solution.

Solve both equations for $x$.

3. David’s last equation to solve is $\frac{x}{100}+\frac{3}{100}=\frac{8}{100}$. Write and solve an equivalent equation with easier numbers that would give him the same answer.

Multiply both sides of the equation by $100$.