CPM Homework Help : CAAC Problem 6-103

Mr. Greer solved an equation below. However, when he checked his solution, it did not make the original equation true. Find his error and then find the correct solution.

$4x=8\left(2x-3\right)$
$4x=16x-3$
$-12x=-3$
$x=\frac{-3}{-12}$
$x=\frac{1}{4}$

Hint:

Check Mr. Greer's distribution. Did he do it correctly?

Help:

Is $8$ times $−3$ equal to $−3$ ?

More Help:

Solve the equation by distributing correctly.