### Home > CAAC > Chapter 8 > Lesson 8.1.3 > Problem 8-31

8-31.

Find the equation of a line perpendicular to the one graphed below that passes through the point (6, 2). Homework Help ✎

Find the slope of the line at right by making a slope triangle.

Use the *y* = *mx* + *b* form of a line to start writing your equation.

Use the opposite reciprocal of the slope you found in order to make the line perpendicular to the one graphed at right.

*y* = −1*x* + *b*

Substitute the given point into the equation to solve for *b*.

2 = −1(6) + *b*

2 = −6 + *b*

8 = *b*

Substitute *y* and *x* back into their original places in the equation, and you have your equation for a line perpendicular to the one that is graphed at right.