### Home > GC > Chapter 1 > Lesson 1.2.2 > Problem1-67

1-67.

For each equation below, find $y$ if $x = −3$. Homework Help ✎

1. $y = −\frac{1}{3}x − 5$

1. $y = 2x^2 − 3x − 2$

c.$2x − 5y = 4$

Substitute $−3$ for $x$ and solve for $y$.

$y=-\frac{1}{3}x-5$

$y=-\frac{1}{3}(-3)-5$

$y=1-5$

$y=-4$

The square of a negative number is always a positive number.

$y = 25$

$y = −2$