### Home > GC > Chapter 1 > Lesson 1.3.1 > Problem1-100

1-100.

Solve the equations below for $x$, if possible. Be sure to check your solution. Homework Help ✎

1. $\frac { 3 x - 1 } { 4 } = - \frac { 5 } { 11 }$

1. $(5 − x)(2x + 3) = 0$

1. $6 − 5(2x − 3) = 4x + 7$

1. $\frac { 3 x } { 4 } + 2 = 4 x - 1$

Multiply both sides of the equation by the lowest common denominator to remove the fraction.

$5-x=0\ \ \ \ \text{ or }\ \ \ \ 2x+3=0$

$\ \ \ \ +x\ \ \ +x\ \ \ \ \ \ \ \ \ \ \ \ -3\ \ \ -3$

$\ \ \ \ \ \ 5=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{2x}{2}=\frac{-3}{2}$

$\ \ \ \ \ \ x=5\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-\frac{3}{2}$

$x = 5 , - \frac { 3 } { 2 }$

Use the zero product property to solve.

Start by distributing the negative $5$.

Multiply both sides of the equation by the lowest common denominator to remove the fraction.