### Home > GC > Chapter 12 > Lesson 12.2.1 > Problem12-60

12-60.

Solve for x.
Is your solution a real number?

$4(x - 3) = 11$

$\underline{\:\:\:\:\:\:\:\:\div4\:\:\:\:\:\div4}$

$x - 3 = \frac{11}{4}$

$x = \frac{23}{4}$

Is it possible for the square or absolute value of a number to be negative?

No real solution, x² must be positive or zero.

Refer to part (a) for help.

Refer to part (b) for help.