### Home > GC > Chapter 7 > Lesson 7.1.3 > Problem7-30

7-30.

Use the Equal Values Method to solve.

$-\frac{1}{3}x+7=-\frac{1}{3}x-2$

7 ≠ -2

There is no solution because 7 ≠ -2. The lines are parallel, so there is no point of intersection.

Use the Equal Values Method to solve.

0 = x² - 4x

0 = x(x - 4)

Therefore, x = 0 or 4, and y = 2(0) + 3 = 3 or
y = 2(4) + 3 = 11.
So there are two points of intersection (0,3) and (4,11).