### Home > MC1 > Chapter 2 > Lesson 2.4.1 > Problem2-130

2-130.

Cecil now has a tightrope that is $59$ feet long.

1. Cecil makes seven jumps (all the same length) and walks $3$ feet to reach the end and go down the ladder. How long is each jump?

A diagram like the one below should help.

Before Cecil had to walk $3$ feet, how far had he jumped?

If Cecil made $7$ jumps that were all the same length to go $56$ feet, how long was each jump?

$59$ feet $−$ $3$ feet $=$ $56$ feet

$\frac{56}{7}=8$

$8$ feet per jump

2. If $x$ represents the length of one jump and $2x$ represents the length of two jumps, write an expression that represents Cecil's journey across the rope.

If you did $3$ jumps and then walked $5$ feet the expression would be $3x+5$.