Home > MC1 > Chapter 7 > Lesson 7.2.2 > Problem7-56

7-56.

Mr. Nowlin has a rectangular garden with an area of $45$ square feet and a length of $10$ feet.

1. What is the width of the garden?

If the area of something is equal to its length times its width (area $=$ (length) (width)), then what times $10$ will equal $45$?
Try using division to find the solution to this problem.

The width of the garden is $4.5$ feet.

2. What is the garden's perimeter?

Remember, the perimeter of a shape is the distance around it. Try adding the lengths of the garden's sides together!