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Home > MC1 > Chapter 7 > Lesson 7.2.2 > Problem 7-56

7-56.

Mr. Nowlin has a rectangular garden with an area of 45 square feet and a length of 10 feet.

  1. What is the width of the garden?

    If the area of something is equal to its length times its width (area = (length) (width)), then what times 10 will equal 45?
    Try using division to find the solution to this problem.

    The width of the garden is 4.5 feet.

  2. What is the garden's perimeter?

    Remember, the perimeter of a shape is the distance around it. Try adding the lengths of the garden's sides together!