Cisco and Janet spent an afternoon making burritos and then put them all on one plate. Six burritos have beef inside, $17$ have chicken filling, and $2$ have black-bean filling. Find the probability of randomly choosing the following burritos from the plate, and write your answer as a fraction, decimal, and percent.

1. A burrito with black bean filling.

   Step 1(a):

   Find the total number of burritos and the number of black bean burritos.

   $6 + 17 + 2 = 25$

   2 black bean burritos

   Step 2(a):

   State the probability as a fraction.

   $\frac{2}{25}$

   Step 3(a):

   Convert the fraction to a decimal and a percent.

   $\left(\frac{2}{25}\right)\left(\frac{4}{4}\right)=\frac{8}{100}=0.08=8\%$

   Answer (a):

   $\frac{2}{25}, \ 0.08, \ 8\%$

2. A burrito that does not have beef filling.

   Hint (b):

   Find the number of burritos that do not have beef filling and repeat the same steps as in part (a).

   Answer (b):

   As a decimal, the probability of picking a burrito without beef filling is $0.76$.
   Can you write this as a fraction and a percent?