Convert both terms to equivalent fractions with a denominator of 12.

$\left(\frac{2}{3}\right)\left(\frac{4}{4}\right)+\left(\frac{3}{4}\right)\left(\frac{3}{3}\right)=\frac{8}{12}+\frac{9}{12}$

Add like parts.

$\frac{8}{12}+\frac{9}{12}=\frac{17}{12}$

$\frac{17}{12}=1\frac{5}{12}$

Remember that dividing by a fraction is the same as multiplying by its reciprocal.
How could you rewrite this division problem as a multiplication problem?

$\left(\frac{2}{3}\right)\left(\frac{4}{3}\right)=\frac{8}{9}$

Convert the mixed number to a fraction greater than one before multiplying.

Remember that the product of two negative numbers is positive.