Home > MC1 > Chapter 9 > Lesson 9.2.4 > Problem9-89

9-89.

Find the missing value in each of the pairs of equivalent ratios below.

1. $\frac { x } { 10 } = \frac { 6 } { 15 }$

If this were an equivalent fraction problem, how would you find the value of $x$?

Think about what values would go in a Giant One to turn tenths into fifteenths.

$\left(\frac{x}{10}\right)\left(\frac{1.5}{1.5}\right)=\frac{6}{15}$

This problem becomes $x\left(1.5\right) = 6$. What number multiplied by $1.5$ gives $6$?
You can also notice that $10$ is two-thirds of $15$ and think about what number is two-thirds of $6$.

$x = 4$

1. $\frac { 12 } { 9 } = \frac { 8 } { x }$

This problem is very similar to part (a).

$x = 6$

1. $\frac { 16 } { 38 } = \frac { 200 } { m }$

How could you use a Giant One to find the value of $m$?