Home > MC2 > Chapter 11 > Lesson 11.3.1 > Problem11-82

11-82.

The two triangles below are similar.

1. Find the area of each triangle.

$\frac{1}{2} (\text{base})(\text{height})$

Area A $= 72 \text{ un}^{2}$
Area B $= 40.5 \text{ un}^{2}$

2. What is the scale factor for the side lengths of the two triangles?

Find the ratio between one of the pairs of
corresponding sides for the two triangles.

Use $\frac{6}{8}$ or $\frac{13.5}{18}$.

What do you get after simplifying?

$\frac{3}{4}$

3. What is the ratio of the areas ($\frac { \text { Area B} } { \text { Area A} }$)? How is this ratio related to the ratio you found in part (b)?

How can you change the scale
factor to get this area ratio?

$\frac{40.5}{72} = \frac{9}{16}$