### Home > MC2 > Chapter 7 > Lesson 7.1.1 > Problem7-9

7-9.

Solve the equations below for the variable. Be sure to check your answer.

1. $3(2x-1) + 2 = 5x$

1. $600x + 200 = 500x$

Distribute.

Combine like terms.

Subtract $5x$ from each side.

Add $1$ to each side.

$3(2x) − 3(1) + 2 = 5x$

$6x − 3 + 2 = 5x$

$6x − 1 = 5x$

$−5x + 6x − 1 = 5x −5x$
$x − 1 = 0$

$x − 1 = 0 +1 +1$

$x = 1$

Divide each term by $100$.

Substitute 1 back into the original equation to check your answer.
$3(2(1)-1) + 2 = 5(1)$
When you simplify this expression, do you get the same values on each side?