### Home > CC1MN > Chapter 6 Unit 6 > Lesson CC1: 6.1.1 > Problem6-7

6-7.

Simplify each numerical expression.

1. $| 5 - 6 + 1 |$

Simplify within the absolute value signs first.

$|5 − 6 + 1| = |0|$

The absolute value of $0$ is $0$.

2. $2|-16.75|$

First, find the absolute value of$−16.75$.

The absolute value is the distance a number is away from $0$.
It is always a non-negative number.
Since $−16.75$ is $16.75$ units away from zero, the absolute value is $16.75$.
What is the product of 2(16.75)?

3. $| 6 \frac { 3 } { 8 } - 2 | + | - 8 \frac { 5 } { 8 } + ( - 1 ) |$

Simplify within the absolute value signs first.

$6\frac{3}{8}-2=\frac{51}{8}-\frac{2}{1}=\frac{51}{8}-\frac{16}{8}=\frac{35}{8}$

$-8\frac{5}{8}+(-1)= -\frac{69}{8}+\left(-\frac{1}{1}\right)=-\frac{69}{8}+\left(-\frac{8}{8}\right)=-\frac{77}{8}$

$\text{Therefore, we have: } \left | \frac{35}{8} \right |+\left | -\frac{77}{8} \right |$

What is the absolute value for each of these numbers?

$14$