### Home > CC1MN > Chapter 8 > Lesson 8.2.1 > Problem8-74

8-74.

Are the following expressions equivalent?

$3(4x-2)+8$

$2(6x+1)$

Substitute $1$ for $x$ into both expressions.
$3(4(1) − 2) + 8 = 3(4 − 2) + 8 = 3(2) + 8 = 14$
$2(6(1) + 1) = 2(7) = 14$

Now substitute $2$ for $x$.
$3(4(2) − 2) + 8 = 3(8 − 2) + 8 = 3(6) + 8 = 26$
$2(6(2) + 1) = 2(12 + 1) = 26$

You can try other values for $x$. It appears they are the same.