Home > CC2MN > Chapter 11 > Lesson 11.1.4 > Problem11-59

11-59.

The figures below are similar. Use the information given about the lengths of the sides to solve for $x$ and $y$

Use proportions to solve for $x$ and $y$.

$\frac{6}{10}=\frac{\it y}{15}$

$10y=90$

$y=9$