CPM Homework Help : CC2MN Problem 6-47

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6-47.

Simplify each expression.

$\frac { 9 } { 15 } \div \frac { 4 } { 3 }$
Hint (a):
When you divide by a fraction, you are multiplying by its reciprocal.
Answer (a):
$\frac{9}{20}$

$- \frac { 19 } { 20 } + \frac { 4 } { 5 }$
Hint (b):
Find a common denominator.
Answer (b):
$-\frac{3}{20}$

$-\frac{8}{9}\div\left(-\frac{2}{5}\right)$
Hint (c):
See part (a).

$3 \frac { 1 } { 2 } \div 1 \frac { 1 } { 7 }$
Hint (d):
Convert these mixed numbers into fractions greater than one.
Answer (d):
$\frac{49}{16}$

$-\frac{3}{4}-\left(-\frac{11}{16}\right)$
Hint (e):
This is the same as $-\frac{3}{4}+\frac{11}{16}$ .
Answer (e):
$-\frac{1}{16}$

$\frac{2}{9}\cdot\frac{14}{15}\cdot\left(-\frac{9}{10}\right)$
Hint (f):
$\frac{2}{9}\Big(-\frac{9}{10}\Big)\cdot\frac{14}{15}$

$-10\frac{4}{5}+\left(-\frac{3}{8}\right)$
Hint (g):
You may add whole numbers and fractions separately.
$(-10)+\left(-\frac{4}{5}+-\frac{3}{8}\right)$
Answer (g):
$-11\frac{7}{40}$

$\frac{12}{5}\div\left(-\frac{1}{10}\right)$
Hint (h):
See part (a).

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