CPM Homework Help : CC2MN Problem 9-93

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Home > CC2MN > Chapter 9 > Lesson 9.3.1 > Problem 9-93

9-93.

Solve the equations below for the variable. Be sure to check your answer.

$3(2x-1)+2=5x$
Step 1 (a):
Distrubute.
$\begin{array}{r} 3(2x)-3(1)+2=5x\\ 6x-3+2=5x \end{array}$
Step 2 (a):
Combine like terms.
$6x-1=5x$
Step 3 (a):
Subtract $5x$ from each side.
$\begin{array}{l} -5x+6x-1=5x-5x\\ \qquad \quad \; \; x-1=0 \end{array}$
Step 4 (a):
Add $1$ to each side.
$x-1+1=0+1+1$
Answer (a):
$x=1$
Check:
Substitute $1$ back into the original equation to check your answer.
$3\left(2\left(1\right)-1\right)+2=5\left(1\right)$
When you simplify this expression, do you get the same values on each side?

$600x+200=500x$
Hint (b):
Divide each term by $100$ .

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