CPM Homework Help : CC2MN Problem 9-97

Copy and complete each of the Diamond Problems below. The pattern used in the Diamond Problems is shown at right.

Generic Diamond Problem. One number, X, is located on the left side. The second number, Y, is located on the right side. The bottom number is the sum of the two numbers, X and Y. The top number is the product of the two numbers, X and Y.

Hint (a):
Converting the mixed number into a fraction greater than one may prove to be helpful.
More Help (a):
$\left(\frac{6}{5}\right)\left(\frac{3}{4}\right) = ?$
$\frac{6}{5} + \frac{3}{4} = ?$
Answer (a):
Top: $\frac{9}{10}$
Bottom: $\frac{39}{20}$

Hint (b):
$\frac{2}{5} + ? = \frac{11}{15}$
Answer (b):
Top: $\frac{2}{15}$
Right: $\frac{1}{3}$

Hint (c):
Use the method presented in part (a).

Hint (d):
Use the method presented in part (a).