### Home > CC3MN > Chapter 5 > Lesson 5.2.4 > Problem5-60

5-60.

Solve for $x$.

1. $\frac { 2 } { 3 } = \frac { x } { 4 }$

Multiply both sides by a common multiple of the denominators in order to get rid of the fractions.

Divide both sides by $3$ to solve for $x$.

$8=3x$

$x = \frac{8}{3}$

1. $\frac { 2 } { 3 } = \frac { x } { 4 } + \frac { x } { 3 }$

Multiply both sides by a common multiple of the denominators in order to get rid of the fractions.

$8=3x+4x$

Combine like terms.

$8=7x$

Divide both sides by $7$ to solve for $x$.

$x=\frac{8}{7}$

1. How are these problems the same and how are they different?

What did you do different in part (b)?