### Home > CC3MN > Chapter 6 Unit 10 > Lesson INT1: 6.4.1 > Problem6-121

6-121.

Solve each equation below for the indicated variable.

1. $4x − 2 + y = 6 − 2x\ \text{for}\ y$

Add $2$ to both sides.
$4x+y=8−2x$

Subtract $4x$ from both sides.

$y=8−6x$

1. $4x−2+y=6−2x\ \text{for}\ x$

Follow the steps in part (a).

$x = -\frac{1}{6}y+\frac{8}{6}$

1. $3(6 − x) + 2x = 15\ \text{for}\ x$

Multiply to remove the parentheses then follow the steps in part (a).