### Home > CC3MN > Chapter 8 Unit 8 > Lesson CC3: 8.3.1 > Problem8-133

8-133.

Solve each equation below for the given variable. Be sure to check your solution.

1. $6x − 11 = 3x + 16$

Isolate x on one side and simplify.

1. $−2\left(5 − 3x\right) + 5 = 9 + 3x$

Distribute −2 first, then isolate x and simplify.

$−10 + 6x + 5 = 9 + 3$x

1. $\frac { 6 } { k - 2 } = 10$

How can you remove the fraction?

You can multiply both sides by $k − 2$.

$({\it k}-2)\frac{6}{{\it k}-2}=10({\it k} - 2)$

$6 = 10\left(k − 2\right)$
Now simplify.

$6 = 10k − 20$
$26 = 10k$

${\it k} = \frac{13}{5} = 2.6$

1. $\frac { 4 } { 3 x - 1 } = \frac { 2 } { x + 3 }$

How can you remove the fractions?

You can use cross multiplication.
$4\left(x + 3\right) = 2\left(3x − 1\right)$

$x = 7$
Remember to show your work.