
Home > CCA2S > Chapter A > Lesson A.2.2 > Problem A-68
A-68.
7 − 4 = 10 − 7 = 13 − 10 = 3
m = 3
t(n) = 3n − t(0)
t(0) = 4 − 3 = 1
t(n) = 3n + 1
m = 5
t(n) = 5n − 2
m = −5
t(n) = −5n + 29
9.5 − 7 = 12 − 9.5 = 2.5
m = 2.5
t(0) = 7 − 2.5 = 4.5
t(n) = 2.5n + 4.5