### Home > INT1 > Chapter Ch8 > Lesson 8.2.3 > Problem 8-120

8-120.

*BE* is the midsegment of Δ*ACD*, shown below. What is the perimeter of Δ*ACD*? Homework Help ✎

The perimeter of Δ*ACD* = (2)(the perimeter of Δ*ABE*) because the midsegment cuts the sides in half.