### Home > CA > Chapter Ch7 > Lesson 7.3.4 > Problem7-114

7-114.
1. Use the point-slope formula (presented in the Math Notes box for this lesson) to find the equation of each line below. Homework Help ✎

1. The line with slope that goes through the point (–6, 5).

2. A horizontal line that goes through the point (8, –11).

3. The line perpendicular to the line in part (a) above but going through the origin.

Substitute the slope and the points into the point slope formula.

yk = m(xh)

$y-5 = -\frac{2}{3}(x + 6)$

$y-5 = -\frac{2}{3}x-4$

$y = -\frac{2}{3}x + 1$

Substitute the slope (0 for a horizontal line) and the points into the point slope formula.

y + 11 = 0(x − 8)
yk = m(xh)
y + 11 = 0
y = −11

See parts (a) and (b) to solve. Remember that perpendicular lines have opposite reciprocal slopes.